What is 64/16 + 3/10?

This is how you add

Step 1

We still have different denominators (bottom numbers), though, so we need to get a common denominator. This will make the bottom numbers match. Multiply the denominators together first. Now, multiply each numerator by the other term's denominator.

Now we multiply 64 by 10, and get 640, then we multiply 16 by 10 and get 160.

Now for the second term. You multiply 3 by 16, and get 48, then multiply 16 by 10 and get 160.

This gives us a new problem that looks like so:

Step 2

Since our denominators match, we can add the numerators.

640 + 48 = 688

So what's the answer so far?

Step 3

Can this fraction be reduced?

First, we attempt to divide it by 2...

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

Let's try dividing by that again...

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

Let's try dividing by that again...

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

Let's try dividing by that again...

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

Let's try dividing by that again...

Nope! So now we try the next greatest prime number, 3...

Nope! So now we try the next greatest prime number, 5...

Nope! So now we try the next greatest prime number, 7...

Nope! So now we try the next greatest prime number, 11...

No good. 11 is larger than 10. So we're done reducing.

There you have it! Here's the final answer to 64/16 + 3/10