Let's add
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Step 1Now we need to make our denominators match. 40 goes into 10 evenly, so we only need to multiply one term to get a common denominator. Multiply 3 by 4, and get 12, then we multiply 10 by 4 and get 40. This gives us a new problem that looks like so:
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Step 2Since our denominators match, we can add the numerators. 4 + 12 = 16 That gives us an answer of
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Step 3Can this fraction be reduced? First, we attempt to divide it by 2... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Let's try dividing by that again... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Let's try dividing by that again... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Let's try dividing by that again... Nope! So now we try the next greatest prime number, 3... No good. 3 is larger than 2. So we're done reducing. There you have it! Here's the final answer to 4/40 + 3/10
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