This is how to add
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Step 1We still have different denominators (bottom numbers), though, so we need to get a common denominator. This will make the bottom numbers match. Multiply the denominators together first. Now, multiply each numerator by the other term's denominator. Now we multiply 20 by 10, and get 200, then we multiply 64 by 10 and get 640. Now for the second term. You multiply 3 by 64, and get 192, then multiply 64 by 10 and get 640. This gives us a new problem that looks like so:
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Step 2Since our denominators match, we can add the numerators. 200 + 192 = 392 That gives us an answer of
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Step 3Can this fraction be reduced? First, we attempt to divide it by 2... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Nope. Try the next prime number, 3... Nope. Try the next prime number, 5... Nope. Try the next prime number, 7... Nope. Try the next prime number, 11... Nope. Try the next prime number, 13... Nope. Try the next prime number, 17... Nope. Try the next prime number, 19... Nope. Try the next prime number, 23... Nope. Try the next prime number, 29... Nope. Try the next prime number, 31... Nope. Try the next prime number, 37... Nope. Try the next prime number, 41... Nope. Try the next prime number, 43... Nope. Try the next prime number, 47... Nope. Try the next prime number, 53... No good. 53 is larger than 49. So we're done reducing. Congratulations! Here's your final answer to 20/64 + 3/10
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