 # What is 7/16 + 2/12? 7 16
+
 2 12

## Step 1

We still have different denominators (bottom numbers), though, so we need to get a common denominator. This will make the bottom numbers match. Multiply the denominators together first. Now, multiply each numerator by the other term's denominator.

Now we multiply 7 by 12, and get 84, then we multiply 16 by 12 and get 192. Now for the second term. You multiply 2 by 16, and get 32, then multiply 16 by 12 and get 192. This gives us a new problem that looks like so:

 84 192
+
 32 192

## Step 2

Since our denominators match, we can add the numerators.

84 + 32 = 116

So what's the answer so far?

 116 192

## Step 3

Can this fraction be reduced?

First, we attempt to divide it by 2...

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

 116 192
÷ 2 =
 58 96

Now, try the same number again.

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

 58 96
÷ 2 =
 29 48

Now, try the same number again.

Nope. Try the next prime number, 3...

Nope. Try the next prime number, 5...

Nope. Try the next prime number, 7...

Nope. Try the next prime number, 11...

Nope. Try the next prime number, 13...

Nope. Try the next prime number, 17...

Nope. Try the next prime number, 19...

Nope. Try the next prime number, 23...

Nope. Try the next prime number, 29...

Nope. Try the next prime number, 31...

No good. 31 is larger than 29. So we're done reducing.