Here's how we add
|
||||||||||||||||||||||||||||||||
Step 1We still have different denominators (bottom numbers), though, so we need to get a common denominator. This will make the bottom numbers match. Multiply the denominators together first. Now, multiply each numerator by the other term's denominator. Now we multiply 2 by 10, and get 20, then we multiply 12 by 10 and get 120. Now for the second term. You multiply 1 by 12, and get 12, then multiply 12 by 10 and get 120. This gives us a new problem that looks like so:
|
||||||||||||||||||||||||||||||||
Step 2Since our denominators match, we can add the numerators. 20 + 12 = 32 That gives us an answer of
|
||||||||||||||||||||||||||||||||
Step 3Can this fraction be reduced? First, we attempt to divide it by 2... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Nope. Try the next prime number, 3... Nope. Try the next prime number, 5... No good. 5 is larger than 4. So we're done reducing. Congratulations! Here's your final answer to 2/12 + 1/10
|