Here's how we add
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Step 1We still have different denominators (bottom numbers), though, so we need to get a common denominator. This will make the bottom numbers match. Multiply the denominators together first. Now, multiply each numerator by the other term's denominator. Now we multiply 1 by 12, and get 12, then we multiply 10 by 12 and get 120. Now for the second term. You multiply 2 by 10, and get 20, then multiply 10 by 12 and get 120. This gives us a new problem that looks like so:
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Step 2Since our denominators match, we can add the numerators. 12 + 20 = 32 That gives us an answer of
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Step 3Can this fraction be reduced? First, we attempt to divide it by 2... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Now, try the same number again. Nope. Try the next prime number, 3... Nope. Try the next prime number, 5... No good. 5 is larger than 4. So we're done reducing. Congratulations! Here's your final answer to 1/10 + 2/12
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