What is 4/40 + 2/11?
|
Let's add
|
|||||||||||||||||||||||||
Step 1We still have different denominators (bottom numbers), though, so we need to get a common denominator. This will make the bottom numbers match. Multiply the denominators together first. Now, multiply each numerator by the other term's denominator. Now we multiply 4 by 11, and get 44, then we multiply 40 by 11 and get 440. Now for the second term. You multiply 2 by 40, and get 80, then multiply 40 by 11 and get 440. This gives us a new problem that looks like so:
|
|||||||||||||||||||||||||
Step 2Since our denominators match, we can add the numerators. 44 + 80 = 124 That gives us an answer of
|
|||||||||||||||||||||||||
Step 3Can this fraction be reduced? First, we attempt to divide it by 2... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Let's try dividing by that again... Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
Let's try dividing by that again... Nope! So now we try the next greatest prime number, 3... Nope! So now we try the next greatest prime number, 5... Nope! So now we try the next greatest prime number, 7... Nope! So now we try the next greatest prime number, 11... Nope! So now we try the next greatest prime number, 13... Nope! So now we try the next greatest prime number, 17... Nope! So now we try the next greatest prime number, 19... Nope! So now we try the next greatest prime number, 23... Nope! So now we try the next greatest prime number, 29... Nope! So now we try the next greatest prime number, 31... Nope! So now we try the next greatest prime number, 37... No good. 37 is larger than 31. So we're done reducing. There you have it! Here's the final answer to 4/40 + 2/11
|