 # What is 1/12 + 2/10? 1 12
+
 2 10

## Step 1

We still have different denominators (bottom numbers), though, so we need to get a common denominator. This will make the bottom numbers match. Multiply the denominators together first. Now, multiply each numerator by the other term's denominator.

Now we multiply 1 by 10, and get 10, then we multiply 12 by 10 and get 120. Now for the second term. You multiply 2 by 12, and get 24, then multiply 12 by 10 and get 120. This gives us a new problem that looks like so:

 10 120
+
 24 120

## Step 2

Since our denominators match, we can add the numerators.

10 + 24 = 34

That gives us an answer of

 34 120

## Step 3

Can this fraction be reduced?

First, we attempt to divide it by 2...

Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:

 34 120
÷ 2 =
 17 60

Now, try the same number again.

Nope. Try the next prime number, 3...

Nope. Try the next prime number, 5...

Nope. Try the next prime number, 7...

Nope. Try the next prime number, 11...

Nope. Try the next prime number, 13...

Nope. Try the next prime number, 17...

Nope. Try the next prime number, 19...

No good. 19 is larger than 17. So we're done reducing.